Question

using prime factos method find HCF
1 ) 5and 25
2) 3 and 16
3 ) 4 and 28​

Answer 1

Answer:

1) 5

2)Co-prime

3)4

Step-by-step explanation:

1) P.F of 5=5

P.F of 25=5×5

C.F= 5

H.C.F=5

2)P.F of 3=3

P.F=2×2×2×2

they are Co-prime. means they have no common factor (C.F)

3)P.F of 4=2×2

P.F of 28=2×2×7

C.F=2×2

H.C.F=4

Answer 2

1 ) 5and 25

5=5

25=5*5

HCF is 5

2) 3 and 16

3=3*1

16=2*2*2*2

HCF is 1

3 ) 4 and 28

4=2*2

28= 2*2*7

HCF is 2*2=4

Hope it helps you.......