Using properties of pertect squares write the ones place disit of the squares of the following (i) 425 (ii) 637 (iii) 896 (iv) 1741
please full solve tomorrow is my paper
Answers
Answered by
1
Answer:
5² = 25
7² = 49
6² = 36
1² = obviously 1
HOPE IT WILL HELP U
Answered by
0
Step-by-step explanation:
in one's place there are 5,7,6,1
therefore
5square =25
seven square =49
six square =36
and
1square =1
Similar questions