Question

using properties of square and square roots find 100^2 - 98^2​

Answer 1

$\huge{ \underline{ \bf \orange{question}}}$

${100}^{2} - {98}^{2}$

$\huge{ \underline{ \bf \green{answer}}}$

This can be solved by the simple algebraic identity of :

$(a + b) \: and \: (a - b)$

$\small{ \underline{ \bf \blue{why \: this \: identity}}}$

We must use this identity as :

A = 100

B = 98

When we use this we get :

(100+98) (100-98)

198 × 2

=396

# mark it as the BRAINLIEST

# thank toh kardo bhai

Answer 2

Answer:

396 is the value of $100^2 - 98^2$.

Step-by-step explanation:

Explanation:

Given, $100^2 - 98^2$

According to the  question we need to find the value of $100^2 - 98^2$ by the help of  properties of square  and square roots

Properties of square and square roots

• Only a perfect square number can have a perfect square root.

• Even perfect squares have an even square root.

• At their unit location, square numerals always conclude with the digits 0, 1, 4, 5, 6, or 9.

• There will be an odd square root for an odd perfect square.

Step 1:

We have, $100^2 - 98^2$.

⇒$100^2 - 98^2$

• As we know, when a number is multiplied by itself, the result is a square number.

• For instance, 25 is a square number since it is composed of 5 lots of 5, or 5 × 5.

So,  $100^2 - 98^2$ can be written as,

⇒ 100× 100 - 98× 98

⇒10000 - 9604    

⇒396    

Final answer:

Hence,the value of $100^2 - 98^2$ is 396.

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