using quadratic formula find root of 2/3x=-1/6x²-1/3
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if it helps mark me brainliest
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achyut21:
yar tumne formula galat lagaya hai but thnx because my main problem was doing in LCM
kaun sa formula
x= -b+- √b²-4ac/2a
bhai alpha and beta are two values which you obtain on solving your answer . i only make it seperate
ok
thnx bhai
Answered by
5
2/3x=-1/6x^2-1/3
2x/6x^2=-1/6x^2-2x^2/6x^2
2x=-1-2x^2
2x^2-2x+1=0
Now roots
alfa+beta=b/a=-2/2=-1
ab=-c/a=-1/2
I think it is helpful for you
2x/6x^2=-1/6x^2-2x^2/6x^2
2x=-1-2x^2
2x^2-2x+1=0
Now roots
alfa+beta=b/a=-2/2=-1
ab=-c/a=-1/2
I think it is helpful for you
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