Question

using quadratic formula find x^2-14+45=0​

Answer 1

$x^2-14+45=0$

$x^2-14+45-\left(-14+45\right)=0-\left(-14+45\right)$

$x^2=-31$

$\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$x=\sqrt{-31},\:x=-\sqrt{-31}$