Question

using quadratic formula solve for x abx 2 +(b 2 -ac)x-bc=0

Answer 1

B 2+a 2 c 2 this is the correct of this question

Answer 2

Given: $\sf{{abx}^{2} + ( {b}^{2} - ac)x - bc = 0}$

$\longrightarrow$$\sf{{abx}^{2} + {b}^{2} x - acx - bc = 0}$

$\longrightarrow$$\sf{bx(ax + b) - c(ax - b) = 0}$

$\longrightarrow$$\sf{(ax + b)(bx - c) = 0}$

$\longrightarrow$$\sf{ax + b = 0 \: or \: bx - c = 0}$

Hence, the solutions are $\sf{x = - \frac{b}{a} \: and \: x = \frac{c }{b}}$