Question

Using quadratic formula solve :- p²x²+(p²-q²)x - q²

Answer 1

Answer:

Step-by-step explanation:

b²-4ac

=(p²-q²)²- 4(p²)(-q²)

=p⁴+q⁴-2p²q²+4p²q²

=p⁴+q⁴+2p²q²

Since, b²-4ac >0

Hence, x=-b±√b²-4ac/2a

=-(p²-q²)±√p⁴+q⁴+2p²q²/2(p²)

=-p²+q²±(p²+q²)/2p²

x=q²-p²-p²-q²/2p²

x=-2p²/2p²

x=-1

Also,x=-q²+p²-p²-q²/2p²

=-2q²/2p²

x=-q²/p²

..Hope it will help...

Answer 2

p²x²+(p²-q²)x - q²

Solution:

here,

the value of a is p².

the value of b is (p²-q²)

the value of c is q²

we know the formula of quadratic equation,

b²-4ac=0---> A)

now put the values of a, b, c in equation A)

(p²-q²)²-4*p²*q²=0

so that ,,

x=-b±√b²-4ac/2a

=-(p²-q²)±√p^4+q^4+2p²q²/2(p²)

=-p²+q²±(p²+q²)/2p²

x=q²-p²-p²-q²/2p²

x=-2p²/2p²

x=-1

x=-q²+p²-p²-q²/2p²

=>-2q²/2p²

x=-q²/p²

so, its the solution