Question

using quadratic formula, solve the following ..

Answer 1

Which one to solve?

Anyways I am solving both.

7.  36x² + 23 = 60x
36x² - 60x + 23 = 0
Here
a = 36, b = - 60, c = 23
x = [- b ± √(b² - 4ac)]/2a
x = [- (-60) ± √((-60)² - 4*36*23)]/2*36
x = [60 ± √(3600 - 3312)]/72
x = [60 ± √288]/72
x = (60 + 16.97)/72 or (60 - 16.97)/72
x = 1.069 or 0.597


8. x² - 2x + 5 = 0
Here
a = 1, b = - 2, c = 5
x = [-b ± √(b² - 4ac)]/2a
x = [ - (- 2) ± √((- 2)² - 4*1*5)]/2*1
x = [2 ± √(4 - 20)]/2
x = (2 ± √-16)/2
x = (2 + √-16)/2 or (2 - √-16)/2

Hope this helps you.