Question

using remainder theorem check whether the polynomial 2x^3 - 2ax^2 - 6x + 6a ia a multiple of x-a

Answer 1

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Answer 2

x-a=0
X=a
2xcube-2a(x)square-6x+6a=
2acube-2acube-6a+6a
=0
remainder is 0 So the polynomial is divisible by x-a