Using remainder theorem, factorise: 2x 3 -13x 2 +26x-15
Answers
Answered by
55
P(x) = 2 x³ - 13 x² + 26 x - 15
for x =1, P(x) = 0 . Hence (x-1) is a factor.
P(x) = (x - 1) (2 x² - a x + 15)
= 2x³ - (a +2) x² + (a+15) x - 15
comparing coefficients : a = 11
hence : 2 x² - 11 x + 15
2 x² - 6 x - 5 x + 15
2 x (x - 3) - 5 ( x -3)
Hence factors are : ( x - 1)( 2x - 5) ( x - 3)
for x =1, P(x) = 0 . Hence (x-1) is a factor.
P(x) = (x - 1) (2 x² - a x + 15)
= 2x³ - (a +2) x² + (a+15) x - 15
comparing coefficients : a = 11
hence : 2 x² - 11 x + 15
2 x² - 6 x - 5 x + 15
2 x (x - 3) - 5 ( x -3)
Hence factors are : ( x - 1)( 2x - 5) ( x - 3)
Answered by
15
Answer:Hi there
Ans is (x-1)(x-3)(2x-5)
Step-by-step explanation:
P(x) = 2 x³ - 13 x² + 26 x - 15
for x =1, P(x) = 0 . Hence (x-1) is a factor.
P(x) = (x - 1) (2 x² - a x + 15)
= 2x³ - (a +2) x² + (a+15) x - 15
comparing coefficients : a = 11
hence : 2 x² - 11 x + 15
2 x² - 6 x - 5 x + 15
2 x (x - 3) - 5 ( x -3)
Hence factors are : ( x - 1)( 2x - 5) ( x - 3)
Similar questions
India Languages,
8 months ago
English,
8 months ago
Chemistry,
8 months ago
Science,
1 year ago
Science,
1 year ago