Question

Using remainder theorem, factorize completely x3 + x2 - 4x -4.​

Answer 1

Answer:

x=2;[x-2=0]

therefore x-2 is a factor

(x3+x2-4x-4) ÷(x-2)

(x2+3x+2) *(x-2)

(x2+2x+x+2) *(x-2)

[x(x+2) +1(x+2) ]*(x-2)

[(x+1) (x+2) ]*(x-2)

hence,

after factorising completely

x3+x2-4x-4=(x+1) (x+2) (x-2)