Question

using remainder theorem find the remainder on dividing 3x2 + 5x - 11 by 2x + 5​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

The remainder obtained on dividing 3x² + 5x - 11 by 2x + 5​ =  $\frac{-19}{4}$

Step-by-step explanation:

Recall the theorem

When a polynomial f(x) is divided by a linear polynomial x-a, the remainder will be equal to f(a)

Given,

f(x) = 3x²+5x-11

2x +5 = 0 ⇒ x =( $\frac{-5}{2}$) ⇒ x-( $\frac{-5}{2}$) = 0

The by remainder theorem,

The remainder obtained when f(x) is divided by  x-( $\frac{-5}{2}$) is f( $\frac{-5}{2}$)

f( $\frac{-5}{2}$) = 3($\frac{-5}{2}$)²+5( $\frac{-5}{2}$)-11

= 3 × $\frac{25}{4}$ - $\frac{25}{2}$ - 11

= $\frac{75 - 50 -44}{4}$

= $\frac{-19}{4}$

∴ The remainder obtained on dividing 3x² + 5x - 11 by 2x + 5​ =  $\frac{-19}{4}$

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