using remainder theorem , find the remainder when x^4-3x^3+2x^2-4 is divided by x+2
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Let,
given polynomial be
and g(x) = (x - 2)
Then,
P(x) is divided by g(x)
For finding the zero of g(x), put g(x) = 0
x - 2 = 0
=> x = 2
So,
it is the zero of g(x).
On putting (x - 2) in [ Equation.(i) ] , we get
Hence, the value of p(2) is 1, which is the required remainder obtained on dividing.
Step-by-step explanation:
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