Question

using remainder theorem find the remainders when f(x) is divided by g(x)
f(x) =x⁴-3x²+4
g(x) =x-2​

Answer 1

Answer:

when f( x) =x⁴-3x²+4 is divided by g(x) =x-2 by long division method . the remainder is 2

Step-by-step explanation:

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Answer 2

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ANSWER ::

The zero of the polynomial x - a is given by

x - 2 = 0

So

x = 2

Let f(x) = x⁴ - 3x² + 4

Now by the Remainder Theorem the required Remainder is

f(2) = 2⁴ - 3× 2² + 4 = 16 - 12 + 4 = 8