Question

using remainder therom , find remainder when 3x^2+x+7 is divided by x+2 ​

Answer 1

Divided= 3x^2+x+7

Divisor= X+2=0 so, X= -2

remainder = p(-2)= 3(-2)²+(-2)+7

=12-2+7

=3

so remainder is 3. please mark as brainliest and follow me and thank my maximum answer

Answer 2

Step-by-step explanation:

p(x) = (3x)2+x+7

g(x)=x+2

Now,x+2=O

x= -2

so, using x= -2 in p(x)

3(-2)2 + (-2)+ 7

=3×4-2+7

=12-2+7

=19-2= 17

so ,the remainder is 17.

hope it helps.