Question

using rules for special products, evaluate$101 x^{2}$

Answer 1

I think the question is $101^2$

It can be written as $(100+1)^2$

Using the special product formula $(a+b)^2 = a^2 + 2ab + b^2$

$(100+1)^2 = 100^2 + 2(100)(1) + 1^2$
             
                        = 10000 + 200 + 1
           
                       = 10201

So $(101)^2 = 10201$