Question

Using SAS property prove that triangle formed by joining the mid point of sides of a triangle is similar to other four triangle


........please answer fast​

Answer 1

By mid-point formula,

AD //FE. AD=FE=1/2 AB

DE//BC. DE = AF =1/2AC = 1/2AB

=>AD =DE. AD//DE

=>AFED is a //gm.

=>an. BAC = an. DEF (Opposite sides of Parallelogram are equal)

So,

Similarly,

By SAS similarity,

tr. DEF ~ tr. CAB ~tr. FAD~ tr. CFE~tr. EDB.

Hope this will help you. 

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