Question

using second law of motion derive the relation between force and acceleration . if A bullet of 10 gram strikes a sand bags at a speed of 500 m per second and gets embedded after travelling 5 cm find:- a) the resistive force exerted by the sand on the bullet. b) the time taken by the bullet to come at rest

Answer 1

According to second law of motion

Force is directly proportional to rate of change of momentum

so,

F ~ dp/dt

we know that momentum

p = mv

so,

F = d(mv)/dt = m[dv/dt]

thus, we get

F = ma
According to second law of motion

Force is directly proportional to rate of change of momentum

so,

F ~ dp/dt

we know that momentum

p = mv

so,

F = d(mv)/dt = m[dv/dt]

thus, we get
I hope it will help
F = ma

Answer 2

Hope it helps you......