Using section formula prove that the points (2,3,4) ,(-1,2,-3) and (-4,1,-10) are collinear.
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The given points are A(2,−3,4),B(−1,2,1) and C(0, 3,1,2)
Let P be a point that divides AB in the ratio k:1.
Using section formula, the coordinates of P are given by,
( k+1k(−1)+k+1k(2)−3k+1k(1)+4 )
Now, we will find the value of k at which point P coincides with point C.
⇒ k+1−k+2
=0, we get k=2
For k=2, the coordinates of point P are (0, 1/3,2),
i.e., C(0,1/3 ,2) is a point that divides AB externally in the ratio 2:1 and is the same as point P
Hence, points A,B and C are collinear
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