using section formula show that points A(2,-3,4), B(-1,2,1), C(0,1/3,2) are collinear
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For such a question we can use LINEAR SCALE FACTOR whereby you divide the bigger number with the smaller number in order to get the common scale factor, if AB gives you the same as AC then the points A,B and C are collinear but if not the points are not collinaer, see the solution below;
Point AB = B/A
A(2,-3,4) and B(-1,2,1)
i)-1/2=-1/2
ii)2/3=2/3
iii)1/4=1/4
Point BC= C/B
i)0/-1=0
ii)1/3/2=1/6
iii)2/1=2
The points AB and BC already confirms that the points A,B and C are not collinear since the division of there co-ordinates does not give out a common factor.
Point AB = B/A
A(2,-3,4) and B(-1,2,1)
i)-1/2=-1/2
ii)2/3=2/3
iii)1/4=1/4
Point BC= C/B
i)0/-1=0
ii)1/3/2=1/6
iii)2/1=2
The points AB and BC already confirms that the points A,B and C are not collinear since the division of there co-ordinates does not give out a common factor.
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