Question

using section formula, show that the points A(-3,1), B(1,3), C(-1,1 are collinear ​

Answer 1

Answer:

value of k=1 hence proved that they are collinear

Step-by-step explanation:

(k-3/k+1),(3k-1/k+1)=the coordinates

c=(-1,1)=c=(k-3/k+1),(3k-1/k+1)

on equating x-coordinate from both sides,we get

-1=(k-3/k+1)

-k-1=k-3

=-2k=-3+1

=-2k =-2

=k=1

on equating y-coordinate from both the sides,we get

1=(3k-1/k+1)

=k+1=3k-1

=2k=2

k=1

since,in both the sides the value f k is same .so,c divides AB in the ratio 1:1:1,c is the midpoint of AB

hence A,B C,are collinear

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Answer 2

Step-by-step explanation:

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