Question

Using stoichiometry, determine the mass of powdered drink mix needed to make a 1.0 M solution of 100 mL. powdered drink mix is (C12H22O11).

Answer 1

Answer:

34.2 g

Explanation:

molarity = given mass / molar mass * 1000/ vol(ml)

substituting given values

1=x/342*1000/100           ( molar mass of C12H22O11 = 342)

on solving

x= 34.2 g

Answer 2

Answer:

Molar concentration can be determined by the following equation:

c= n

-------

V

, where n - amount in moles, V - volume of solution in liters.

n = m

------

M

, where m - mass of powdered drink mix, and M - molar mass of powdered drink mix.

Thus, c= m

-------

M.V

M(C12H22O11) = 12 × 12 g + 22 × 1 g +

------ -----

mol mol

11×16 g = 342 g

----- --------

mol mol

m= M×V× c

= 342 g × 0.1 L × 1.0 mol

------- -------

mol L

= 34.2 g

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