Math, asked by rathnakarkotian31, 7 months ago

using suitable identities find. 1) (x²-y) (x²+y) 2) 89² 3) 101². anwser allll and fast plz​

Answers

Answered by SandeepAW
1

Answer:

1) (x²-y)(x²+y).

It is in the form of (a-b)(a+b)=a²-b².

(x²-y)(x²+y)=(x²)²-(y)².

=x⁴-y².

2) 89².

(80+9)².

It is in the form of (a+b)²=a²+b²+2ab.

(80+9)²=(80)²+(9)²+2(80)(9).

=6400+81+1440.

=7921.

3) 101².

(100+1)².

It is in the form of (a+b)²=a²+b²+2ab.

(100+1)²=(100)²+(1)²+2(100)(1).

=10000+1+200.

=10201.

I think this is your answer.

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