Question

Using suitable identity evaluate 101 x102

Answer 1

Answer:

101 x 102 = (100 + 1)(100 + 2)

this is of the form (x+a)(x+b)= x2 +(a+b)x + ab

so, (100)2 + (1+2)100 + 1x2

=10000+ 300 + 2

= 10302.

Answer 2

Answer:

Let 101 be written as ( 100 + 1 )

Let 102 be written as ( 100 + 2 )

⇒ 101 × 102 ⇒ ( 100 + 1 ) × ( 100 + 2 )

• Using Formula ( x + a ) × ( x + b ) = $x^{2} + x( a + b ) + ab$

⇒ ( 100 + 1 ) × ( 100 + 2 )

⇒ $100^{2}$ +[ 100 × ( 1 + 2 ) ] + ( 1 × 2 )

⇒ 10000 + ( 3 × 100 ) + 2

⇒ 10000 + 300 + 2

⇒ 10302

∴ Answer is 10302

----------------------------------------------------------------------------------------------

Hope It Helps You ! :D

By Abhiram5566

                                MARK ME AS BRAINLIEST ANSWER

----------------------------------------------------------------------------------------------