Math, asked by 5382GSATYASRIDEEPTHI, 2 months ago

Using suitable identity, evaluate the following. 103³

(ii) 101 x 102 (iii) 999²​

Answers

Answered by spratia14
5

Step-by-step explanation:

101*102=(100+1) (100+2)

(x+a) (x+b)= x²+x(a+b)+ab

10000+100(1+2)+1*2

10000+100(3)+2

10000+300+2

10302

(103)³=(100+3)³

(a+b)³= a³+b³+3ab(a+b)

1000000+9+3*100*3(100+3)

1000000+9+900(103)

1000000+9+92700

1,092,709

(999)²=(1000-1)²

(a-b)²=a²+b²-2ab

1000000+1-2*1000*1

1000000+1-2000

1000001-2000

998,001

Hope it helps u . dear if u want 7 clas videos u may subscribe my channel smart start

Answered by Creative3d
5

Answer:

PLEASE REFER TO THE ABOVE ATTACHMENT!!!!!

hope \: it \: helps \: you.

Attachments:
Similar questions