Using suitable identity, evaluate the following. 103³
(ii) 101 x 102 (iii) 999²
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Answered by
5
Step-by-step explanation:
101*102=(100+1) (100+2)
(x+a) (x+b)= x²+x(a+b)+ab
10000+100(1+2)+1*2
10000+100(3)+2
10000+300+2
10302
(103)³=(100+3)³
(a+b)³= a³+b³+3ab(a+b)
1000000+9+3*100*3(100+3)
1000000+9+900(103)
1000000+9+92700
1,092,709
(999)²=(1000-1)²
(a-b)²=a²+b²-2ab
1000000+1-2*1000*1
1000000+1-2000
1000001-2000
998,001
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Answered by
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