using suitable identity find (x+y+z)2-(x-y-z)2
Answers
Answered by
110
apply the formula
a=x+y+z
b=x-y-z
therefore...,
=(x+y+z+[x-y-z])(x+y+z-[x-y-z])
=(2x)(2y+2z)
=4xy+4xz
.
.
hope it helps you...
a=x+y+z
b=x-y-z
therefore...,
=(x+y+z+[x-y-z])(x+y+z-[x-y-z])
=(2x)(2y+2z)
=4xy+4xz
.
.
hope it helps you...
Answered by
1
Answer:
Step-by-step explanation:
a=x+y+z
b=x-y-z
therefore...,
=(x+y+z+[x-y-z])(x+y+z-[x-y-z])
=(2x)(2y+2z)
=4xy+4xz
hope it helps
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