Question

Using the factors theorem, factorize
2x^3+11x^2-26x-35

Answer 1

Given,

2x^3 + 11x^2 – 26x – 35,

put x = 1

Then, 2 + 11 – 7 – 6 = 0

since, this equation is divisible by (x – 1).

according to the question,

2x3 + 11x2 – 26x – 35 = (x – 1)(2x^2 + 13x + 35)

= (x – 1)[2x^2 + 12x + x + 35]

= (x – 1)[2x(x + 6) + 1(x + 6)]

= (x – 1)(2x + 1)(x + 6)