Question

Using the formula :-
$\rm \: w = np + \dfrac {1}{2} \: Nx ^{2} \: frame \: a \: formula \: for \: \bf \: x \:$

Solve only if you can . Spam answer will be deleted on the spot . Be brainly ​

Answer 1

$\bold{ \: W= np + \dfrac {1}{2} \: Nx ^{2}}$

$\bold{2(W−np)=NX^2}$

$\bold{X^2 = \frac{2(W - np)}{N}}$

$\bold{X= \sqrt{\frac{2(W - np)} {N}}}$

Answer 2

Question

Using the given formula, frame a formula for 'x' -: $w = np + \dfrac{1}{2}Nx^{2}$

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Answer

Let's solve the equation step-by-step.

$w = np + \dfrac{1}{2}Nx^{2}$

Step 1: Flip the equation.

$\implies w = np + \dfrac{1}{2}Nx^{2}$

$\implies np + \dfrac{1}{2}Nx^{2} =w$

Step 2: Subtract 'np' from both sides of the equation.

$\implies np + \dfrac{1}{2}Nx^{2} - np =w - np$

$\implies \dfrac{1}{2}Nx^{2} =w - mp$

Step 3: Divide '1/2N' from both sides of the equation.

$\implies \dfrac{\frac{1}{2}Nx^{2}}{\frac{1}{2}N} = \dfrac{w - np}{\frac{1}{2}N}$

$\implies x^{2} = \dfrac{w - np}{\frac{1}{2}N}$

Step 4: Simplify the equation.

$\implies x^{2} = \dfrac{w - np}{\frac{1}{2}N}$

$\implies x^{2} = (w - np)\div \frac{N}{2}$

$\implies x^{2} = (w - np)\times \dfrac{2}{N}$

$\implies x^{2} = \dfrac{2w - 2np}{N}$

Step 5: Find square roots of both sides of the equation.

$\implies x^{2} = \dfrac{2w - 2np}{N}$

$\implies \sqrt{x^{2}} = \sqrt{ \dfrac{2w - 2np}{N}}$

$\implies x = \sqrt{ \dfrac{2w - 2np}{N}}$

∴ The formula to find 'x' would be -: $\bf x = \sqrt{ \dfrac{2w - 2np}{N}}$

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