using the identity (a+b) (a-b)=(a^-b^) evaluate 10/3×14/3
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Hey Friend...
Here is the Solution..
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Identity to be used = (a + b )(a - b) = a² - b²
__________
So, let 10/3 = a + b
and 14/3 = a - b
⇒ a + b = 10/3
⇒ a - b = 14/3
Adding both equations
⇒ 2a = 24/3
⇒ a = 4
∴ b = -2/3
(To find the values of a and b above can be done in rough)
____________
Now we have
( 4 + (-2)/3)(4 - (-2)/3) = 4² - (-2/3)²
⇒ (4 - 2/3)(4 + 2/3) = 4² - (-2/3)²
4² - (-2/3)²
⇒ 16 - 4/9
⇒ (144 - 4)/9
⇒ 140/9
________________________
Ans = 140/9
...........
I Hope This Will Help You
Thanks
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