Math, asked by mubash0904, 8 months ago

using the identity (a+b) (a-b)=(a^-b^) evaluate 10/3×14/3

Answers

Answered by QwertyPs
0

Hey Friend...

Here is the Solution..

Lets See...

Identity to be used = (a + b )(a - b) = a² - b²

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So, let 10/3 = a + b

and 14/3 = a - b

⇒ a + b = 10/3

⇒ a - b = 14/3

Adding both equations

⇒ 2a = 24/3

⇒ a = 4

∴ b = -2/3

(To find the values of a and b above can be done in rough)

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Now we have

( 4 + (-2)/3)(4 - (-2)/3) = 4² - (-2/3)²

(4 - 2/3)(4 + 2/3) = 4² - (-2/3)²

4² - (-2/3)²

⇒ 16 - 4/9

⇒ (144 - 4)/9

⇒ 140/9

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Ans = 140/9

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I Hope This Will Help You

Thanks

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