Question

Using the identity (a+b) (a-b) = a² - b²,find
(3m/2+2m/3) (3m/2-2m/3) ​

Answer 1

Answer:

$\frac{25m^{2} }{12}$

Step-by-step explanation:

$(\frac{3m}{2} + \frac{2m}{3} )(\frac{3m}{2} - \frac{2m}{3}) = (\frac{3m}{2})^{2} - (\frac{2m}{3})^{2} = \frac{9m^{2} }{4} - \frac{4m^{2} }{9} = \frac{81m^{2}-16m^{2} }{36} =\frac{65m^{2}}{36} = \frac{25m^{2}}{12}$

Thanks.