Using the measures of the angles
given in the figure alongside, find
the measures of the remaining threeangles.
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1
Given,
∠AOB = 8y
∠FOE = 4y
∠COD = 6y
Find: the angles.
∠AOB = ∠EOD (vertically opposite angles)
hence,
∠FOE + ∠EOD + ∠COD = 180° (linear pair)
4y + 8y + 6y = 180
18y = 180
y =
y = 10
Therefore the angles are :
8y = 8(10) = 80°
4y = 4(10) = 40°
6y = 6(10) = 60°
Hope it helps
have a great day!
Answered by
1
Angle AOB=80.
Angle COD=60.
Angle FOE=40.
Angle EOD=80.
Angle AOF=60.
Angle BOC=40.
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