using the Pythagoras Theorem find the length of the hypotenuse of a right angled triangle sides are 40 cm and 9 CM
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Pythagorus Theorem => C² = A² + B²
∴ C² = 40² + 9²
=> C²= 1681
=> C= √1681
=> C= 41
∴ C² = 40² + 9²
=> C²= 1681
=> C= √1681
=> C= 41
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hello there !!!
In a rt.∆ ABC ,
let AB = 9cm , BC = ? and AC = 40 cm
By PGT,
H² = B² + P²
AC² = AB² + BC²
( 40 ) ² = ( 9)² + BC²
BC² = (40)² - (9)²
= ( 40 +9) (40 -9)
49 × 31 = 196
BC = 14 CM
Hope it helps you
Lokeshkorampalli:
your answer is wrong because the told you to find it hypotenuse not B or P
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