Question

❤❤using the quadratic formula , solve the equation

√3x^² + 11x + 6√3 = 0

Answer 1

Answer :-

the given equation in the form of quadratic equation is :-

$\sqrt{3 {x}^{2} } +11 x + 6 \sqrt{3} = 0$

On the equation comparing with
$a {x}^{2} + bx + c = 0$

we find from the equation

a = √3 , b = 11 and c = 6√3

putting the values of a , b, c in the quadratic equation ,

$x = \frac{ - b ±\sqrt{ {b}^{2} + 4ac } }{2a}$

= > $\frac{ x = - 11 ± \sqrt{( {11}^{2}) - 4( \sqrt{3}) (6 \sqrt{3} )} }{2 \sqrt{3} }$

= $\frac{ - 11 ± \sqrt{121 - 72} }{2 \sqrt{3} } \\ \\ = \frac{ - 11 ±\sqrt{49} }{2 \sqrt{3} } \\ \\ = \frac{ - 11 ± 7}{2 \sqrt{3} }$

$x = \frac{ - 11 + 7}{2 \sqrt{3} } \\ \\ = \frac{ - 4}{2 \sqrt{3} } \\ \\ = \frac{ - 2}{ \sqrt{3} }$

Or,

$x = \frac{ - 11 - 7}{2 \sqrt{3} } \\ \\ = \frac{ - 18}{2 \sqrt{3} } \\ \\ = \frac{ - 9}{ \sqrt{3} }$

$therefore \: \frac{ - 2}{ \sqrt{3} } and \: \frac{ - 9}{ \sqrt{3} } are \: the \: required \: solutions \: of \: the \: given \: equation$

by : rishi403

be brainly

Answer 2

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