Question

using the remainder theorem , find the remainder when x cube+4x square-3x+10is divided by (x-4)​

Answer 1

Answer:

$p(x) = x - 4$

$p(4) = {x}^{3} + 4 {x}^{2} - 3x + 10$

Put x=4

${4}^{3} + 4 ({4}^{2} ) - 3(4) + 10$

$64 + 64 - 12 + 10$

$= 138 - 12$

=126

Answer 2

Answer:

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