Using the remainder theorem find the reminders obtained when x³+(Kx+8)x+k is divided by x+1 and x-2.
Hence find k if the sum of the remainders is 1.
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To find:-
k if the sum of the remainders is 1.
Solution:-
Let,
f(x) = x + (kx+8)x+k
when f(x) is divided by (x + 1) by Remainder theorem
Remainder,
=> f(-1) = (-1)³+{k (-1)+8)} (-1) + k
=> f(-1) = -1+(-k + 8) (-1)+k
=> f(-1)= -1+k-8+k
=> f(-1) = 2k-9
when f (x) is divided by (x - 2),
Remainder,
=> f(2) = (2) + (k.2 + 8) 2+ k
=> f(2) =b8+4k+16+k
=> f(2) = 5k + 24
Also, sum of remainders = 1
=> f(-1) + f(2) = 1
=> 2k - 9 +5k + 24 = 1
=> 7k + 15 = 1
=> 7k =1-15
=> k = -14/7
=> k =-2
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