Question

using the substitution method, solve pair of simultaneous equation. x/3+y/2=4,2/3x-y/6=1. ​

Answer 1

Answer:

Solution

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(i) x+y=5 ...(i)

2x−3y=4 ...(ii) (elimination method)

Multiply eqn (i) by 2

2x+2y=10

2x−3y=4

−+−

____________

5y=6

⇒y=

5

6

Substitute y=

5

6

in eqn (i)

x+y=5

x+

5

6

=5

⇒x=

5

5×5

−

5

6

=

5

19

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