Question

Using velocity of light, mass of particle and Planck's constant, the expression for a quantity whose dimensions is length

Answer 1

The answer is provided in the attachment.

PLEASE MARK AS BRAINLIEST

Answer 2

Concept:

• Using dimensional analysis
• Identifying the correct dimensions of a physical quantity

Given:

• The velocity of light v
• Planck's Constant h

Find:

• The expression for a quantity whose dimensions is length [L]

Solution:

Velocity of light has the following dimension v = [LT^-1]

Planck's constant has the following dimension h = [ML^2T^-1]

Let the expression for the quantity be x = v^a *h^b

[L] =  [LT^-1]^a *[ML^2T^-1]^b

[L] =  [L^aT^-a] *[M^bL^2bT^-b]

[L] =  [L^(a+2b)T^(-a-b) * M^b]

[LT^0 M^0] =  [L^(a+2b)T^(-a-b) * M^b]

On comparing both expressions, we get

h/v = [ML^2T^-1]/[LT^-1]

h/v = [ML]

h/mv =  [ML]/[M]

h/mv = L

The correct expression for the physical quantity is h/mv where m is the mass.

#SPJ3