Using your knowledge on Hess's law and the two equations given below, calculate the enthalpy change of the following reaction:
S(s) + O2(g) → SO2(g
S(s) + 3 2 O2(g) → SO3(g) ∆H = -395.2 kJ
2 SO2(g) + O2(g) → 2 SO3(g) ∆H = -198.2 kJ
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Answer:
S(s) + O2(g) → SO2 (g) ∆H = ‐296.8 kJ
2SO2 + O2 → 2SO3 ∆H = ‐198.4 kJ
Write the equation for the formation of sulfur trioxide gas from sulfur solid and oxygen. What is the ∆H of that equation2 S(s) + 3 O2(g) → 2 SO3
We can use Hess’s Law to determine the enthalpy change of the overall reaction from the given reactions:
1. S(s) + O2 (g) → SO2 (g) ∆H = ‐296.8 kJ
2. 2 SO2 + O2 → 2 SO3 ∆H = ‐198.4 kJ
We now need to find a combination of reactions that when added up, gives us the overall reaction.
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