Question

Using zeller's formula , find the day for 15/08/1947

Answer 1

Answer: The day for 15/08/1947 is Friday.

Step-by-step explanation:

Let us understand Zeller's formula first :

Zeller’s Rule Formula

F = K + [ $\frac{13M - 1}{5}$ ] + D + [$\frac{D}{4}$] + [$\frac{C}{4}$] – 2C

where,

1) K = Date

In Zellers rule, months start from March.

2) M = Month no.

Month Starts from March in this formula.  M=6  for August Month

3) D = Last two digits of the year

4) C = The first two digits of century

After finding value of F; Now that you have a numerical value for the day, divide the number by 7. We need the remainder only and match it with following data:

1 = Monday

2 = Tuesday

3 = Wednesday

4 = Thursday

5 = Friday

6 = Saturday

7 = Sunday

Let us now calculate the day for 15/08/1947 with the formula above:

Values of K, M, D and C are 15, 06, 47 and 19 respectively.

The formula is,

F = K + [ $\frac{13M - 1}{5}$ ] + D + [$\frac{D}{4}$] + [$\frac{C}{4}$] – 2C

Replacing the values in the formula, we get

F = 15 + [$\frac{(13 X 6) -1}{5}$] + 47 + $\frac{47}{4}$ + $\frac{19}{4}$ – (2 x 19)

Therefore,

F = 15 + $\frac{77}{5}$ + 47 + $\frac{47}4}$ + $\frac{19}{4}$ – 38

Which gives..

F =15 + 15.4 + 47 + 11.75 + 4.75 – 38

[ We Consider only the integral value and ignore the value after decimal]

F =15 + 15 + 47 + 11 + 4 – 38

Therefore, F = 54

Dividing 54 by 7 , we get the remainder as 5.

Referring to the Zeller's formula , 5 represents Friday.

Hence, The day for 15/08/1947 is Friday.

Answer 2

Answer:

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