uuld givell Delow, calculate Karl Pearson's correlation coefficient:
1
2
3
4
5
6
7
8
9
9
8.
10
12
11
13
14
16
15
Ansr
Answers
Answer:
Δ=√s(s−a)(s−b)(s−c).
∴Δ=√6(6−3)(6−5)(6−4)cm2=6×3×1×2 sq.cm
=6 sq.cmΔ=√s(s−a)(s−b)(s−c).
∴Δ=√6(6−3)(6−5)(6−4)cm2=6×3×1×2 sq.cm
=6 sq.cmΔ=√s(s−a)(s−b)(s−c).
∴Δ=√6(6−3)(6−5)(6−4)cm2=6×3×1×2 sq.cm
Δ=√s(s−a)(s−b)(s−c).
∴Δ=√6(6−3)(6−5)(6−4)cm2=6×3×1×2 sq.cm
Δ=√s(s−a)(s−b)(s−c).
∴Δ=√6(6−3)(6−5)(6−4)cm2=6×3×1×2 sq.cm
=6 sq.cmΔ=√s(s−a)(s−b)(s−c).
∴Δ=√6(6−3)(6−5)(6−4)cm2=6×3×1×2 sq.cm
=6 sq.cmΔ=√s(s−a)(s−b)(s−c).
∴Δ=√6(6−3)(6−5)(6−4)cm2=6×3×1×2 sq.cm
Δ=√s(s−a)(s−b)(s−c).
∴Δ=√6(6−3)(6−5)(6−4)cm2=6×3×1×2 sq.cm
Δ=√s(s−a)(s−b)(s−c).
∴Δ=√6(6−3)(6−5)(6−4)cm2=6×3×1×2 sq.cm
Δ=√s(s−a)(s−b)(s−c).
∴Δ=√6(6−3)(6−5)(6−4)cm2=6×3×1×2 sq.cm
Δ=√s(s−a)(s−b)(s−c).
∴Δ=√6(6−3)(6−5)(6−4)cm2=6×3×1×2 sq.cm
=6 sq.cm
=6 sq.cm
=6 sq.cm
=6 sq.cm
=6 sq.cm
=6 sq.cm
=6 sq.cm
Explanation:
ghΔ=√s(s−a)(s−b)(s−c).
∴Δ=√6(6−3)(6−5)(6−4)cm2=6×3×1×2 sq.cm
=6 sq.cm