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A ball is gently dropped from a height of 20 m. If its velocity
increases uniformly at the rate of 10 m s-2, with what velocity
will it strike the ground? After what time will it strike the
ground?
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Answer:
Initial Velocity of ball, u =0
Distance or height of fall, s =20 m
Downward acceleration, a =10 m s-2
As we know, 2as =v2-u2
v2 = 2as+ u2
= 2 x 10 x 20 + 0
= 400
ˆ´ Final velocity of ball, v = 20 ms-1
t = (v-u)/a
ˆ´Time taken by the ball to strike = (20-0)/10
= 20/10
= 2 seconds
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