(v) 107811
= 107811 = (11X11 XILX (3X3X3)x3
Bis left without triplet. Seif
multiply by (383 Jon both sides, them
we will get a perfect cube,
107811 X3X3 = { XLIXU) x (3X3X3)x(3 X3X3)
:: Regismallest no. = 3x3=9
Is it right or wrong???
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