When an air rifle is fired, it exerts an impulse of 0.019 Ns on the pellet.
The pellet has a mass of 1.1 × 10–4 kg.
(a) Determine the speed with which the pellet leaves the rifle.
(b) Determine the kinetic energy of the pellet as it leaves the rifle.
Answers
Answered by
0
Answer:
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Answered by
4
Answer172.73
Explanation:
a. impulse=change in momentum
0.019=1.1*10^-4*v
=172.73m/s
b. K.E=1/2 mv^2
=1/2*1.1*10^-4*(172.73)^2
=7545.6J
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