v^2=2gh
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We can also derive it by following method:- We know that v=u+at Or, [math]t = \frac{v-u}{a}[/math] Distance travelled ... Is it true that v^2=2gh? ... How do you prove that V2=u2+2as using V=u+at?
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Since PE = mgh and KE = ½ mv², then mgh = ½ mv². Note: SQRT(2gh) and √(2gh) means the square root of 2gh. Note that the mass m cancels out of the equation, meaning that all objects fall at the same rate. v = 8 ft/s.
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