Math, asked by amolg9432, 16 hours ago

(v) 2y3 - 2y2 - 5 - 390 + 4y2 + y - 2

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Answered by sapnagharami1706

5

Answer:

2y^3 - 2y^2 - 5 - 390 + 4y^2 + y - 2

2y^3 - 2y^2 + 4y^2 + y - 5 - 390 - 2

2y^3 + 2y^2 + y - 397

Answered by parikumari01022012

1

Answer:

can you please answer my question

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