V=5cos(wt-π/6)and I= 10sin(wt). Then what is the average power dissipated in the circuit
Answers
Answered by
0
A/C to question,
i = 5cosωt
i = 5sin(ωt + π/2) [ we know , sin(90+A) = cosA ]
V = 200sinωt
V = 200sin(ωt + 0)
hence, phase difference between I and V is
Φ = π/2 - 0 = π/2
now, Power loss in circuit = Vi.cosΦ
where V and I are sinusoids rms values, Φ is the phase difference between Voltage and current.
because Φ = π/2 => cosΦ = 0
so, Power loss in circuit = 0
Read more on Brainly.in - https://brainly.in/question/2516656#readmore
Similar questions
English,
6 months ago
India Languages,
6 months ago
Hindi,
11 months ago
Math,
1 year ago
Math,
1 year ago