Question

(v) A truck starts from rest and rolls down a hill with a constant acceleration. It travels a distance
Of 400 m in 20s. Find its acceleration. Find the force acting on it if its mass is 7 tonnes.
(Hint: 1 tonne = 1000 kg)
​

Answer 1

Answer:

Given data:

Mass of stone(m)=7000kg

Distance (s)= 400m

Time(t)=20s

a) we have to find acceleration of the truck?

So from the equation of motion S=ut +1/2a t²,

where u=0

S=½a×t²

a=2×S/t²= 2×400/20×20=2 m/sec²

b) Force acting on a truck

So,from Newton's 2nd law of motion

F=ma=7000×2=14000N=14kN

here's ur answer hope it will help u!!!

Answer 2

Answer:

2m/s²

Explanation:

$s = ut + \frac{1}{2} a {t}^{2}$

s(displacement) = 400m

t(time) = 20s

u(initial velocity) = 0 m/s

400 = 0xt + 1/2 a x 20²

400 = 0 + 1/2 a x 400

400 = a x 1/2 x 400

400 = a x 200

400/200 = a

a = 2m/s²

force acting upon it = ma

= 7000 x 2

= 14000N

= 14KN

Thankyou