Question

v) Masses of three pieces of wires made of the same metal are in the ratio 1:3:5 and their lengths are in the ratio 5:3:1. The ratios of their resistances are
(A) 1:3:5 (B) 5:3:1
(C) 1:15:125 (D) 125:15:1​

Answer 1

Answer:its d)125:15:1

Explanation:Resistance of a wire is given as

ρL/A

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This is the same as

ρL ^2/A×L=ρL ^2/V

So, resistance is proportional to

L ^2/M

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The ratio of resistances is,

25/1:9/3:1/5

​

=125:15:1