Question

(v) p(x) = x2 + 2√2 x - 6​

Answer 1

Answer:

We find the zeroes by factorizing the equation x

2

−x−6=0 as follows:

x

2

−x−6=0

⇒x

2

−3x+2x−6=0

⇒x(x−3)+2(x−3)=0

⇒(x+2)(x−3)=0

⇒x+2=0,x−3=0

⇒x=−2,x=3

Hence, the zeroes of the polynomial x

2

−x−6=0 are 3,−2.

Step-by-step explanation:

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Answer 2

Answer:

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