Question

V-u = at check the correctness of the relation

Answer 1

Answer:

this relation is already correct.

it can also be written as

v = u + at , which is actual form.

Answer 2

Given equation :-

v = u + at

$\rule{150}{2}$

We know,

• dimensional formula of v = (M⁰LT⁻¹)

• dimensional formula of u = (M⁰LT⁻¹)

• dimensional formula of a = (M⁰LT⁻²)

• dimensional formula of t = (M⁰L⁰T)

$\rule{150}{2}$

→ LHS  is the dimensional formula of v = (M⁰LT⁻¹)

→ RHS = dimensional formula of u + dimensional formula of a × dimensional formula of t

= (M⁰LT⁻¹) + (M⁰LT⁻²) × (M⁰L⁰T)

= (M⁰LT⁻¹) + (M⁰LT⁻¹)

= 2(M⁰LT⁻¹)

$\rule{150}{2}$

2 is a dimensionless constant, so LHS = RHS

Hence,the given relationship(equation) is dimensionally correct.